Star network has ( R_A = 2.667\Omega, R_B = 1.333\Omega, R_C = 1.778\Omega ).
In a balanced star-delta network with equal resistors (( R ) in Delta, ( R/3 ) in Star), the star-delta transformation yields symmetry. For a typical bridge problem: star delta transformation problems and solutions pdf
But B connects to L (18Ω) and R (18Ω). So we now have a simpler network: A–N–L–B and A–N–R–B with also L–R via 6Ω? No, L and R are not directly connected after conversion. So combine L and R via B. Star network has ( R_A = 2
RAB×RACRAB+RBC+RCAthe fraction with numerator cap R sub cap A cap B end-sub cross cap R sub cap A cap C end-sub and denominator cap R sub cap A cap B end-sub plus cap R sub cap B cap C end-sub plus cap R sub cap C cap A end-sub end-fraction : If all delta resistors are equal ( RΔcap R sub cap delta ), the star resistor is Star ( ) to Delta ( Δcap delta ) Conversion So we now have a simpler network: A–N–L–B